WebbTo get the product 1, we should multiply (8/21) by (a) 8/21 (b) -8/21 (c) 21/8 (d) -21/8. Answer: (c) 21/8. Because, = (8/21) × (21/8) = (8 × 21) / (21 × 8) = 168/168 = 1. Related Questions. Rational numbers follows x + y = y + x by taking x = ½, y = ½ Webb25 juli 2024 · To get the product 1, we should multiply (8/21) by (a) 8/21 (b) -8/21 (c) 21/8 (d) -21/8. rational numbers; class-8; Share It On Facebook Twitter Email. 1 Answer +1 …
To get the product 1 , we should multiply (-8/21 ) by _____ - Brainly.in
WebbNow, we can multiply numerator with numerator and denominator with denominator. (4/9) × (3/16)= 1/12 In case, if the fraction has no common factors, then we should directly multiply the numerators and denominators to get the product of the fractions. Multiplication of Fractions with Fractions Multiplying Proper Fractions WebbAdd a comment. 0. I did make a very simple definition of product; helpful for "calculating the product of a tuple". def product (tuple1): """Calculates the product of a tuple""" prod = 1 for x in tuple1: prod = prod * x return prod. Might be a more elegant way to do it but this seems to work OK. simply health contact phone number
To get the product 1, we should multiply 8÷21by - Brainly
Webb3 apr. 2024 · Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject … Webb30 apr. 2024 · To get the product 1 , we should multiply 8/21 by Advertisement Expert-Verified Answer 7 people found it helpful mdimtihaz Let the second number be Given: … WebbNotice that the dot product of two n n -tuples of equal length is always a single real number. Check your understanding 1) Let \vec {c}= (4,3) c = (4,3) and \vec {d}= (3,5) d = (3,5). \vec {c}\cdot \vec {d}= c⋅ d = 2) Let \vec {m}= (2,5, -2) m = (2,5,−2) and \vec {n}= (1,8,-3) n = (1,8,−3). \vec {m}\cdot \vec {n} = m⋅n = Matrices and n n -tuples simply health corporate